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`ArrayView<'a, T, D>` is invariant in parameters `T` and `'a`, because `ArrayBase<S, D>` is invariant in the parameter `S` because the array base is using the projection `<S as Data>::Elem` in the struct definition. This means that the equivalent of the `&'a T -> &'b T` conversion (valid whenever `'a: 'b` is not naturally available for array views; we can provide it manually, with a method.
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cc @jturner314; I'm unsure here if "reborrow" is the right name. |
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"reborrow" seems like a good name to me. You are effectively borrowing the data again; the For those not on IRC, this was the case that caused me to encounter the issue. I did find that calling |
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I was really in need of this API some time ago. Thanks for introducing it! :) |
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Good. It is a temporary solution. |
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ArrayView<'a, T, D>is invariant in parametersTand'a, becauseArrayBase<S, D>is invariant in the parameterSbecause the arraybase is using the projection
<S as Data>::Elemin the structdefinition.
This means that the equivalent of the
&'a T -> &'b Tconversion (validwhenever
'a: 'bis not naturally available for array views; we canprovide it manually, with a method.