nll rejects this code

[d653]

UPDATE: Turns out this code should not work, so we just need to add a negative test. See this comment but also the mentoring instructions in this tracking bug.

---

This code compiles, but it does not compile with nll enabled.

#![feature(nll)]
use std::io::{BufRead, BufReader};

fn main() {
    let v = BufReader::new("aaa.bbb\nccc.ddd\neee.fff.ggg\n".as_bytes());
    let _ = v.lines().map(|x:Result<String,_>|{
        let x = x.unwrap();
        move||{x.rsplit(".")}
    });
}

[emilyalbini]

cc @nikomatsakis

[Aaron1011]

I'd like to work on this.

[Aaron1011]

Reduced version:

#![feature(nll)]

fn main() {
    let a = "Hello".to_string();
    move || {
        a.rsplit("")
    };
}

[Aaron1011]

An even simpler reduction:

#![feature(nll)]

fn use_val<'a>(val: &'a u8) -> &'a u8 {
    val
} 

fn main() {
    let orig: u8 = 5;
    move || {
        use_val(&orig)
    };
}

[Aaron1011]

Looking at this some more, I think the error is actually correct. The move closure takes ownership of orig, but then tries to return a reference to it. With ast-borrowck, the closure expression itself compiles, but any attempt to call it results in a similar lifetime error.

It seems to me that the error message itself could be improved, however. In the absence of explicit lifetime parameters, temporary lifetimes like '_#1r and regions without a proper name shouldn't show up in errors.

[daboross]

This code compiles on stable, though. It's still a regression, right? @Aaron1011

Your simple example fails to compile on stable if you run the closure, but the original example given by @gw653 compiles and runs completely fine on stable, and it is running the closure.

Nevermind that, I realized what the code was doing. it's the closure inside the closure that's failing. Changing let _ = to let mut a = and adding (a.next().unwrap())(); causes the original to also fail to compile

[Aaron1011]

@daboross: Given that it's impossible to actually call the closure, I don't feel that this is really a regression. As written, the original example shouldn't be valid - NLL just gives the error 'earlier' than ast-borrowck.

@nikomatsakis: Thoughts?

[nikomatsakis]

@Aaron1011 is correct. If you try to think about the desugaring of the closure expression to the Fn traits, it turns out that there is no legal desugaring of this example. The problem is that the closure C is attempting to return a reference to data owned by self; but the Fn trait looks like this:

trait Fn<A> {
    type Output;
    fn call<'a>(&'a self, args: A) -> Self::Output;
}

In particular, the return type we would need here is &'a u8, but the lifetime 'a is used only in &self and cannot appear in the return type (Self::Output).

The AST-based type-checker has several known flaws in this area, so I'm not surprised to be uncovering bugs in this area. Seems like one we should add to #47366.