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41 lines (35 loc) · 1.05 KB
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Copy pathsymmetricTree.java
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41 lines (35 loc) · 1.05 KB
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
private boolean equalTreeCheck(TreeNode tree1, TreeNode tree2) {
if(tree1 == null && tree2 == null) {
return true;
}
if(tree1 == null || tree2 == null) {
return false;
}
//A slight tweak to the standard inOrderTraversal because the symmetry has to be checked
return (tree1.val == tree2.val &&
equalTreeCheck(tree1.left, tree2.right) &&
equalTreeCheck(tree1.right, tree2.left)
);
}
public boolean isSymmetric(TreeNode root) {
//deleted the redundancies realted to null checks
return equalTreeCheck(root.left, root.right);
}
}
//Solved